Solution:
1) Compare to the series ∑n=1∞ 1/n (harmonic series)
2) limn→∞ [n²/(n³ + 1)] / [1/n] = limn→∞ n³/(n³ + 1) = 1
3) Since the limit is a positive finite number and ∑1/n diverges
4) By the Limit Comparison Test, ∑n=1∞ n²/(n³ + 1) also diverges
Answer: The series diverges
Solution:
1) f(x) = eˣ, so f⁽ⁿ⁾(x) = eˣ for all n
2) f⁽ⁿ⁾(0) = e⁰ = 1 for all n
3) Maclaurin series: eˣ = ∑n=0∞ (1/n!) xⁿ
4) = 1 + x + x²/2! + x³/3! + x⁴/4! + ...
5) For radius of convergence: R = limn→∞ |cₙ/cₙ₊₁| = limn→∞ (n+1) = ∞
6) Therefore, the radius of convergence is ∞ (converges for all x)
Answer: eˣ = ∑n=0∞ xⁿ/n!, R = ∞
Solution:
1) Maclaurin series for sin(x) = x - x³/3! + x⁵/5! - x⁷/7! + ...
2) First three terms: sin(x) ≈ x - x³/6 + x⁵/120
3) For x = 0.1: sin(0.1) ≈ 0.1 - (0.1)³/6 + (0.1)⁵/120
4) = 0.1 - 0.001/6 + 0.00001/120
5) = 0.1 - 0.0001667 + 0.0000000833
6) ≈ 0.0998334
Answer: sin(0.1) ≈ 0.0998334