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Kirchhoff's Laws (KVL and KCL)

Kirchhoff's Laws are fundamental principles for analyzing complex electrical circuits. Kirchhoff's Voltage Law (KVL) states that the sum of voltages around any closed loop equals zero, while Kirchhoff's Current Law (KCL) states that the sum of currents entering a junction equals the sum of currents leaving it.

Kirchhoff's Voltage Law (KVL)

$$\sum V = 0$$

Kirchhoff's Voltage Law states that the algebraic sum of all voltage drops around any closed loop in a circuit equals zero. This means that the sum of voltage rises equals the sum of voltage drops.

šŸŽÆ KVL Statement

Around any closed loop in a circuit, the algebraic sum of all voltage drops equals zero.

This means: Sum of voltage rises = Sum of voltage drops

Sign Conventions for KVL

šŸ“ KVL Sign Convention Rules

Example: KVL in Simple Loop

Problem: Find the current in a circuit with a 12V battery and two resistors (3Ī©, 6Ī©) in series.

diagram
Simple loop with series resistors

Step 1: Choose Loop Direction

Let's traverse the loop clockwise.

Step 2: Write KVL Equation

$$V - I_1R_1 - I_2R_2 = 0$$
$$I_1 = I_2 = I$$
$$+12V - 3I - 6I = 0$$

Explanation:

Step 3: Solve for Current

$$12V - 9I = 0$$ $$9I = 12V$$ $$I = \frac{12V}{9Ī©} = 1.33A$$

Answer

The current in the circuit is 1.33A.

Kirchhoff's Current Law (KCL)

$$\sum I_{in} = \sum I_{out}$$

Kirchhoff's Current Law states that the sum of currents entering a junction equals the sum of currents leaving the junction. This is based on the conservation of charge.

šŸŽÆ KCL Statement

At any junction in a circuit, the sum of currents entering equals the sum of currents leaving.

This means: Charge is conserved at every junction

Sign Conventions for KCL

šŸ“ KCL Sign Convention Rules

Example: KCL at Junction

Problem: Find the unknown current Iā‚ƒ at a junction where I₁ = 2A (entering) and Iā‚‚ = 1.5A (leaving).

example
Junction with three currents

Step 1: Apply KCL

$$I_{in} = I_{out}$$ $$I_{in} = I_a$$ $$I_{out} = I_b+I_c$$

Step 2: Solve for Unknown Current

$$I_c = I_a-I_b$$ $$I_c = 5-3$$ $$I_c = 2$$

Answer

The current Ic is 2A (leaving the junction).

Combined Analysis

When analyzing complex circuits, both KVL and KCL are used together to create a system of equations that can be solved simultaneously.

This video helps to show to problem solving process:

This video is one of my favorites to understand how to solve these types of question:

Systematic Method

  1. Identify loops and junctions
  2. Assign current directions (arbitrary, but be consistent)
  3. Write KVL equations for each independent loop
  4. Write KCL equations for junctions (if needed)
  5. Solve the system of equations

Key Takeaways