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LR Circuits

Overview: Inductor-Resistor Circuits

LR circuits consist of an inductor and resistor connected in series. When a voltage is applied, the current doesn't immediately reach its maximum value due to the inductor's opposition to changes in current. The current increases exponentially with a characteristic time constant.

These circuits are fundamental for understanding how inductors behave in DC circuits and are important for analyzing electromagnetic devices, filters, and power electronics.

Key Formulas

Time Constant

\[ \tau = \frac{L}{R} \]

Where:

Note: This formula is NOT on the AP Physics C equation sheet.

Current as Function of Time

\[ I(t) = \frac{V}{R}(1 - e^{-t/\tau}) \]

Where:

Note: This formula is NOT on the AP Physics C equation sheet.

Key Concepts

Time Constant

The time constant determines how quickly the current changes:

  • After \(\tau\): current reaches 63% of final value
  • After \(2\tau\): current reaches 86% of final value
  • After \(5\tau\): current reaches 99% of final value
  • Larger \(L\) or smaller \(R\): slower current changes

Initial Behavior

When switch is first closed:

  • Current starts at zero
  • Inductor opposes current change
  • Voltage across inductor equals applied voltage
  • Voltage across resistor is zero

Final Behavior

After a long time:

  • Current reaches maximum: \(I = \frac{V}{R}\)
  • Inductor acts like a wire
  • Voltage across inductor is zero
  • Voltage across resistor equals applied voltage

Energy Storage

Energy is stored in the inductor's magnetic field:

  • Energy: \(U = \frac{1}{2}LI^2\)
  • Increases as current increases
  • Maximum when current is maximum

Visualize an inductor at the start as a broken wire, current can't pass through. Once time progresses, current can pass through, acting like a wire.

In this diagram, at the start all the current will flow through the resistor because the inductor acts like a broken wire. After a while, NO current passes through the resistor because it gets short circuted - the inductor is the path of least resistance so all the current passes through there.

Derivations (Not on AP Equation Sheet)

Derivation: Current Formula

Step-by-Step:

  1. Kirchhoff's voltage law: \(V = IR + L\frac{dI}{dt}\)
  2. Rearrange: \(\frac{dI}{dt} = \frac{V - IR}{L}\)
  3. This is a first-order differential equation
  4. Solution: \(I(t) = \frac{V}{R}(1 - e^{-t/\tau})\) where \(\tau = \frac{L}{R}\)

Example Problems

Example 1: Time Constant

Problem: An LR circuit has \(L = 0.5\) H and \(R = 2\) Ω. What is the time constant?

  1. \(\tau = \frac{L}{R} = \frac{0.5}{2} = 0.25\) s

Answer: 0.25 s

Example 2: Current Calculation

Problem: In the above circuit with \(V = 10\) V, what is the current after 0.5 s?

  1. \(I(t) = \frac{V}{R}(1 - e^{-t/\tau}) = \frac{10}{2}(1 - e^{-0.5/0.25})\)
  2. \(I(0.5) = 5(1 - e^{-2}) = 5(1 - 0.135) = 4.33\) A

Answer: 4.33 A

Example 3: Energy Storage

Problem: What is the energy stored in the inductor when current is maximum?

  1. Maximum current: \(I = \frac{V}{R} = \frac{10}{2} = 5\) A
  2. Energy: \(U = \frac{1}{2}LI^2 = \frac{1}{2}(0.5)(5)^2 = 6.25\) J

Answer: 6.25 J

Quiz: LR Circuits

1. What is the time constant for \(L = 2\) H and \(R = 4\) Ω?

0.5 s
2 s
8 s
0.25 s

2. After one time constant, the current reaches:

63% of final value
50% of final value
100% of final value
37% of final value

3. When the switch is first closed, the voltage across the inductor is:

Equal to the applied voltage
Zero
Half the applied voltage
Negative

4. After a long time, the inductor acts like:

A wire
An open circuit
A battery
A resistor

Learning Objectives

Key Takeaways

LR Circuit Interactive Simulation

Explore how current changes over time in an LR circuit:

10.0 V
0.5 H
2.0 Ω
Time Constant: 0.25 s | Max Current: 5.0 A
Voltage Across Inductor
10.0 V
Voltage Across Resistor
0.0 V

Current vs Time Graph

Voltage vs Time Graph