Master advanced coordinate systems and vector calculus
← Back to UnitsUnit 9 explores three powerful mathematical systems: parametric equations for describing curves with a parameter, polar coordinates for circular and spiral patterns, and vector-valued functions for motion in space.
Parametric equations describe curves using a third variable (parameter) t:
Sketch the curve defined by x = t², y = 2t for -2 ≤ t ≤ 2.
Solution:
Create a table of values:
t | x = t² | y = 2t | (x, y) |
---|---|---|---|
-2 | 4 | -4 | (4, -4) |
-1 | 1 | -2 | (1, -2) |
0 | 0 | 0 | (0, 0) |
1 | 1 | 2 | (1, 2) |
2 | 4 | 4 | (4, 4) |
This traces a parabola opening to the right.
For parametric equations x = f(t), y = g(t):
Find dy/dx and d²y/dx² for x = t³ - t, y = t² + 1.
Solution:
1) dx/dt = 3t² - 1, dy/dt = 2t
2) dy/dx = (2t)/(3t² - 1)
3) For second derivative: d²y/dx² = (d/dt)[(2t)/(3t² - 1)] / (3t² - 1)
4) Using quotient rule: d²y/dx² = [(2)(3t² - 1) - (2t)(6t)]/(3t² - 1)³
5) = (6t² - 2 - 12t²)/(3t² - 1)³ = (-6t² - 2)/(3t² - 1)³
Polar coordinates use (r, θ) where:
Convert (3, π/4) to rectangular coordinates.
Solution:
x = 3 cos(π/4) = 3(√2/2) = 3√2/2
y = 3 sin(π/4) = 3(√2/2) = 3√2/2
Rectangular coordinates: (3√2/2, 3√2/2)
The area bounded by the polar curve r = f(θ) from θ = α to θ = β is:
Find the area inside the cardioid r = 2(1 + cos θ).
Solution:
1) The cardioid is traced once as θ goes from 0 to 2π
2) A = (1/2) ∫02π [2(1 + cos θ)]² dθ
3) = (1/2) ∫02π 4(1 + 2cos θ + cos² θ) dθ
4) = 2 ∫02π (1 + 2cos θ + cos² θ) dθ
5) = 2[θ + 2sin θ + (θ/2 + sin(2θ)/4)]02π = 6π
A vector-valued function assigns a vector to each value of a parameter:
For r(t) = ⟨t², 2t, t³⟩, find velocity, speed, and acceleration at t = 1.
Solution:
1) v(t) = r'(t) = ⟨2t, 2, 3t²⟩
2) v(1) = ⟨2, 2, 3⟩
3) |v(1)| = √(2² + 2² + 3²) = √17
4) a(t) = v'(t) = ⟨2, 0, 6t⟩
5) a(1) = ⟨2, 0, 6⟩
Parametric Arc Length:
Polar Arc Length:
Find the arc length of x = t², y = t³ from t = 0 to t = 2.
Solution:
1) dx/dt = 2t, dy/dt = 3t²
2) L = ∫02 √[(2t)² + (3t²)²] dt = ∫02 √(4t² + 9t⁴) dt
3) = ∫02 t√(4 + 9t²) dt
4) Let u = 4 + 9t², then du = 18t dt
5) L = (1/18) ∫440 √u du = (1/18)[(2/3)u^(3/2)]440 = (1/27)(40^(3/2) - 4^(3/2))
Find dy/dx for the parametric equations x = sin(t), y = cos(2t).
Solution:
1) dx/dt = cos(t), dy/dt = -2sin(2t)
2) dy/dx = (dy/dt)/(dx/dt) = (-2sin(2t))/(cos(t))
3) Using double angle identity: sin(2t) = 2sin(t)cos(t)
4) dy/dx = (-2)(2sin(t)cos(t))/(cos(t)) = -4sin(t)
Find the area inside the rose r = 3cos(3θ).
Solution:
1) The rose has 3 petals, traced once as θ goes from 0 to π
2) A = (1/2) ∫0π [3cos(3θ)]² dθ
3) = (9/2) ∫0π cos²(3θ) dθ
4) Using identity: cos²(3θ) = (1 + cos(6θ))/2
5) = (9/4) ∫0π (1 + cos(6θ)) dθ = (9/4)[θ + sin(6θ)/6]0π = 9π/4
A particle moves with position vector r(t) = ⟨t², 2t, t³⟩. Find the speed when t = 2.
Solution:
1) v(t) = r'(t) = ⟨2t, 2, 3t²⟩
2) v(2) = ⟨4, 2, 12⟩
3) |v(2)| = √(4² + 2² + 12²) = √(16 + 4 + 144) = √164 = 2√41
Now that you've mastered parametric equations, polar coordinates, and vector-valued functions, test your understanding with our comprehensive practice test. The test includes:
Ready for the final challenge? Unit 10: Infinite Sequences and Series explores convergence, power series, and Taylor polynomials - the culmination of AP Calculus BC.
Explore Unit 10 →